5x^2-100x+95=0

Solution for 5x^2-100x+95=0 equation:

5x^2-100x+95=0

a = 5; b = -100; c = +95;
Δ = b2-4ac
Δ = -1002-4·5·95
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-90}{2*5}=\frac{10}{10}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+90}{2*5}=\frac{190}{10}
=19
$